Why spectra, and what stabilisation actually buys you
The Freudenthal suspension theorem says that for an -connected space , the suspension map
is an isomorphism for and surjective when . Iterate it and the homotopy groups stop moving. What is left is the stable homotopy group
This is the whole trick, and it is worth being precise about what it costs.
What you gain
Unstably, is a set — pointed, but a set. After stabilisation it becomes an abelian group, and the category of spectra is triangulated: cofibre sequences and fibre sequences agree, so a great deal of homological algebra transfers verbatim. The smash product makes it symmetric monoidal, with the sphere spectrum as unit. Suddenly one can say “module over a ring spectrum” and mean it.
Concretely: the Adams spectral sequence
computes something genuinely hard — the -completed stable homotopy of — from something merely difficult, namely over the Steenrod algebra .
What you lose
Stabilisation is not free. It forgets everything that is not visible after enough suspensions: the Whitehead product dies, and with it much of the unstable information about how is glued together. is still, famously, not fully known.
Why a physicist should care
Anomalies in quantum field theory are classified by bordism groups, and bordism groups are homotopy groups of Thom spectra — . The invariants that a physical theory can actually detect are stable ones, which is a statement about spectra whether or not one chooses to say it that way.
That is roughly the thread I keep pulling on: if the observables are stable invariants, the right home for the question is the stable homotopy category.